Last modified: Dec 04, 2025 By Alexander Williams

Fix TypeError: 'set' object is not subscriptable

You see a TypeError in Python. It says 'set' object is not subscriptable. This error is common. It happens when you try to access a set like a list.

This guide will explain why it happens. You will learn how to fix it. We will cover Python sets and their rules.

What Does This Error Mean?

A subscriptable object allows item access. You use square brackets [] for this. Lists and tuples are subscriptable.

Python sets are not subscriptable. They are unordered collections. You cannot access items by index.

Trying to use [] on a set causes the error. The code fails because sets lack this feature.

Understanding Python Sets

Sets store unique items. They are created with curly braces {} or the set() function. Order is not guaranteed.

Sets are for membership testing. They are for removing duplicates. They are not for indexed retrieval.

This is a key difference from lists. Knowing this prevents the error.


# Creating a set
my_set = {1, 2, 3, 4, 5}
print(type(my_set))
print(my_set)

<class 'set'>
{1, 2, 3, 4, 5}

Common Cause: Direct Indexing

The most direct cause is indexing. You try to get the first item with [0]. This fails immediately.


my_set = {10, 20, 30}
# This will raise the error
first_item = my_set[0]

TypeError: 'set' object is not subscriptable

The error points to the line with my_set[0]. Python tells you the operation is invalid.

How to Fix the Error

You cannot index a set. You must use a different approach. Choose a method based on your goal.

1. Convert Set to List or Tuple

Need indexed access? Convert the set first. Use list() or tuple(). Then use square brackets.

Remember, the order may change. Sets have no inherent order.


my_set = {'apple', 'banana', 'cherry'}
# Convert to a list
my_list = list(my_set)
print(my_list)
# Now you can index
first_fruit = my_list[0]
print(first_fruit)

['banana', 'apple', 'cherry']  # Order may vary
banana

2. Use a For Loop to Iterate

You often just need to process each item. Use a for loop. It works directly on the set.

This is efficient. It uses the set's iterable nature.


unique_numbers = {5, 1, 9}
for num in unique_numbers:
    print(f"Number: {num}")

Number: 1
Number: 5
Number: 9

3. Use Set Methods: pop() and in

To get an arbitrary item, use pop(). To check membership, use the in keyword.

These are the proper ways to interact with a set's elements.


colors = {'red', 'blue', 'green'}
# Get and remove an arbitrary element
some_color = colors.pop()
print(f"Removed: {some_color}")
print(f"Set now: {colors}")

# Check if an element is present
if 'blue' in colors:
    print("Blue is in the set")

Removed: red
Set now: {'green', 'blue'}
Blue is in the set

Debugging in Complex Code

The error can hide in complex logic. You might have a variable that is sometimes a set. Use type() to check.

Ensure your variable is the type you expect. This is good defensive programming.

Similar issues arise with other types. For example, a builtin_function_or_method can cause a related error.


def get_data(source):
    # Imagine this returns different types
    return source

data = get_data({1, 2, 3})  # Could be a set
print(type(data))

# Safe access: check type first
if isinstance(data, set):
    data = list(data)
print(data[0])

<class 'set'>
1

Related TypeErrors in Python

Python has many TypeError messages. They all involve incorrect type operations.

For instance, 'int' and 'str' errors happen with concatenation. 'NoneType' is Not Iterable occurs with loops on None.

Understanding types is key to fixing them all.

Best Practices to Avoid the Error

Know your data structures. Use sets for uniqueness and membership. Use lists for ordered, index-based access.

Plan your data types early. Comment your code. This clarifies the intended structure.

Test with different inputs. Ensure your logic handles all possible types correctly.

Conclusion

The 'set' object is not subscriptable error is straightforward. It means you used [] on a set. Sets do not support indexing.

To fix it, convert the set to a list. Or use iteration and set methods like pop() and in.

Always remember the purpose of each data type. This prevents many common errors like this one and others such as 'tuple' Object Does Not Support Item Assignment.

Keep your code clean and your types clear. Happy coding!